If i = 0, int j= (i++) + (++i) find the value of j

Explanation

The correct option is (c) j = 2.Let's break down the expression to understand how we arrive at the answer:i = 0: This assigns the initial value of 0 to the variable i.(i++): This part uses the post-increment operator. The value of i (which is 0 here) is used in the expression first, and then i is incremented by 1. So, in this case, the value used is 0.(++i): This part uses the pre-increment operator. Here, i is incremented by 1 first (which becomes 1 from the previous step), and then the incremented value (1) is used in the expression.Now, let's evaluate the expression step by step:(i++) + (++i) becomes (0) + (1).Since the post-increment operator uses the value before incrementing, i remains 0 in the first part.The pre-increment operator increments i to 1 before using its value in the second part.Therefore, j = 0 + 1.So, the final value of j is 2.