If an AC voltage of rms value of 10 volts is applied as input of a half-wave rectifier, then the voltage value of the DC output will be:
Correct answer: D. 9.3 V
- A. 10 V
- B. 10.3 V
- C. 10.7 V
- D. 9.3 V
Explanation
Since we have the voltage at AC input, which is 10 V, we just need to subtract this value by the diode drop, which is 0.7 V;10 - 0.7 = 9.3V
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Alternating current varies periodically, so phase relationships become essential when current passes through a resistor, capacitor or inductor. The chapter distinguishes resistance from capacitive and inductive reactance, explains phase lead and lag, and connects changing electric and magnetic fields with the production and properties of electromagnetic waves.
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