If a radioactive isotope of silver has a half-life of about 7.5 days. After 15 days, the remaining isotope of its original is:
Correct answer: A. 25%
- A. 25%
- B. 7.5%
- C. 50%
- D. 15%
Explanation
No. of half-lives = t/T1/2 = 15/ 7.5 = 2No. of atoms of isotopes remaining after 2 half-lives = (1/22)No= 25% of No
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