A nuclide 86220 R decays to a new nuclide by two α-emissions, the nuclide S is:
Correct answer: C. C option
- A. A option
- B. B option
- C. C option
- D. D option
Explanation
After two α-emissions, the values for nuclide S would be:Atomic number (Z): 86 - (2 * 2) = 86 - 4 = 82Mass number (A): 220 - (2 * 4) = 220 - 8 = 212
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