If a process is both endothermic and spontaneous, then:
Correct answer: A. ∆S > 0
- A. ∆S > 0
- B. ∆S < 0
- C. ∆H < 0
- D. ∆G > 0
Explanation
As ∆G = ∆H - T∆SFor spontaneous process, ∆G = negative For endothermic process, ∆H = positive Therefore, ∆S > 0
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About Thermochemistry and Energetics of Chemical Reactions
Thermochemistry measures energy changes in chemical reactions and distinguishes exothermic from endothermic processes. Work covers systems, surroundings and state functions, internal energy, the first law of thermodynamics, enthalpy and Hess's law, including the sign conventions used when heat enters or leaves a system.
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