If a colour­blind man marries a woman who is homozygous for normal color vision, the probability of their son being colour­blind is:

Correct answer: A. 0

  • A. 0
  • B. 0.5
  • C. 0.75
  • D. 1

Explanation

Color blindness is X-linked recessive. A homozygous normal mother (XX) cannot pass the mutant X; sons get father's Y and mother's normal X so 0% affected sons.

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About Inheritance

Mendel's laws explain segregation, independent assortment and the prediction of genetic ratios using alleles, genotypes and phenotypes. The chapter also covers linked genes, recombination and crossing over during meiosis, then applies pedigree reasoning to X-linked recessive traits, which show different inheritance patterns in males and females.

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