If a car at rest accelerates uniformly to a speed of 144km/h in 20 s. Then it covers a distance of
Correct answer: C. 400 m
- A. 20 m
- B. 1440 m
- C. 400 m
- D. 2880 m
Explanation
The car starts from rest, so the initial velocity (u) is 0 m/s. The final velocity (v) is 144 km/h, which converts to 40 m/s. The time (t) is 20 seconds. Using the first equation of motion, v = u + at, we calculate the acceleration (a) as 2 m/s². Then, using the second equation of motion, s = ut + 0.5at², we find the distance covered (s) is 400 m. Option C is the correct answer. Options A, B, and D are incorrect as they result from incorrect calculations or application of the formulas.
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