If a body starts from rest and travels 120 cm in the 6th second, then what is the acceleration
Correct answer: B. 0.218 m / s2
- A. 0.20 m / s2
- B. 0.218 m / s2
- C. 0.027 m / s2
- D. 0.03 m / s2
Explanation
To find the acceleration, use the formula for the distance covered in the nth second of uniformly accelerated motion, which is given by: sn = u + (a/2)(2n - 1), where u is the initial velocity (0 m/s since the body starts from rest), a is the acceleration, n is the nth second (6 in this case), and sn is the distance covered in the nth second (120 cm or 1.2 m).Substitute these values into the equation: 1.2 = 0 + (a/2)(2*6 - 1), which simplifies to 1.2 = a(11/2). Solving for a gives a = 0.218 m/s2.Options A, C, and D are incorrect because they do not satisfy the equation derived from the given formula.
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