If 2uF and 4 uF capacitors connected in series. Their equivalent capacitance will be:
Correct answer: C. 1.33 uF
- A. 8uF
- B. 0.75 uF
- C. 1.33 uF
- D. 6μF
- E. 2 μF
Explanation
When capacitors are connected in series, the inverse of the equivalent capacitance is equal to the sum of the inverses of the individual capacitances. For two capacitors connected in series with capacitances 2 μF and 4 μF, the equivalent capacitance (C_eq) can be calculated as: 1/C_eq = 1/2 + 1/4 Simplifying this equation: 1/C_eq = 2/4 + 1/4 1/C_eq = 3/4 C_eq = 4/3 μF Therefore, the equivalent capacitance of the 2 μF and 4 μF capacitors connected in series is: 1.33 μF. As it is a numerical only one option C is correct
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