A proton of charge 1.6 x 10^-19 C is moved through a potential difference of 20 volt The energy gained by the proton is:

Correct answer: B. 32 x 10^-19J

  • A. -32 x 10^-19J
  • B. 32 x 10^-19J
  • C. -32 x 10^19 J
  • D. 32 x 10^19 J
  • E. Zero

Explanation

The energy gained by a charged particle when it is moved through a potential difference can be calculated using the equation: Energy = charge (q) * potential difference (V). In this case, the charge of the proton is 1.6 x 10^(-19) C, and the potential difference is 20 volts. Plugging in these values into the equation, we get: Energy = (1.6 x 10^(-19) C) * (20 V). Calculating this expression, we find: Energy = 3.2 x 10^(-18) J. Therefore, the energy gained by the proton is 3.2 x 10^(-18) joules. As it is a numerical only one option B is correct.

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