How many moles of oxygen gas are needed for' combustion of 2 moles of propane?
Correct answer: B. 10
- A. 8
- B. 10
- C. 12
- D. 14
Explanation
C₃H₈ + 5O₂ → 3CO₂ + 4H₂OThis equation tells us that 1 mole of propane (C₃H₈) reacts with 5 moles of oxygen gas (O₂) .Since we have 2 moles of propane, we need to multiply the amount of oxygen needed by 2:2 moles C₃H₈ x (5 moles O₂ / 1 mole C₃H₈) = 10 moles O₂Therefore, you need 10 moles of oxygen gas for the combustion of 2 moles of propane.
Last updated
About Chemistry of Hydrocarbons
Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
Practise Chemistry of Hydrocarbons
1,091 free Chemistry of Hydrocarbons MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1-Butene and two Butene are showing which type of isomerism?
1-butyne and 2-butyne can be identified by using which of the following reagents
2-chloropropane is heated with Na metal product is 2,3-dimethyl butane, reaction is:
2-methyl propene is isomeric with but-1-ene. They can be distinguished by:
2-methyl propene is isomeric with butene-1. They can be distinguished by: