How many moles of oxygen gas are needed for' combustion of 2 moles of propane?
Correct answer: B. 10
- A. 8
- B. 10
- C. 12
- D. 14
Explanation
C₃H₈ + 5O₂ → 3CO₂ + 4H₂OThis equation tells us that 1 mole of propane (C₃H₈) reacts with 5 moles of oxygen gas (O₂) .Since we have 2 moles of propane, we need to multiply the amount of oxygen needed by 2:2 moles C₃H₈ x (5 moles O₂ / 1 mole C₃H₈) = 10 moles O₂Therefore, you need 10 moles of oxygen gas for the combustion of 2 moles of propane.
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Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
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