Asked in ETEA MDCAT 2009 2009Moderate

Horizontal range of projectile is:

Correct answer: C. R = V² Sin (2∅)/g

  • A. R= V²sin∅ Cos∅/g
  • B. R= V²i Sin ∅/2g
  • C. R = V² Sin (2∅)/g
  • D. R= V² i sin ∅ (2∅)/g

Explanation

The correct equation for the horizontal range of a projectile is: R = V²sin(2∅)/g where: R is the horizontal range of the projectile (the distance traveled horizontally) V is the initial velocity of the projectile ∅ is the angle of projection (the angle between the initial velocity and the horizontal) g is the acceleration due to gravity.

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About Projectile Motion

Projectile motion combines uniform horizontal motion with vertically accelerated motion under gravity, assuming air resistance is neglected. Questions use the components of initial velocity to find time of flight, maximum height, horizontal range and position, while distinguishing projectile motion from general circular or one dimensional motion.

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