In order to determine the maximum height of the projectile, the equation of motion used is:
Correct answer: B. 2aS = vf2 - vi2
- A. aS = vf2 - vi2
- B. 2aS = vf2 - vi2
- C. 2S = a(vf2 - vi2)
- D. aS = 2(vf2 - vi2)
Explanation
The correct answer is Option B: 2aS = vf2 - vi2. This is the third equation of motion, which is crucial for determining the maximum height of a projectile as it connects initial and final velocities with acceleration and displacement. Option A is incorrect as it does not represent any standard motion equation. Options C and D are incorrect because they misplace the terms of acceleration and displacement, making them non-standard and unusable for calculating projectile motion.
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About Projectile Motion
Projectile motion combines uniform horizontal motion with vertically accelerated motion under gravity, assuming air resistance is neglected. Questions use the components of initial velocity to find time of flight, maximum height, horizontal range and position, while distinguishing projectile motion from general circular or one dimensional motion.
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