A football is kicked at 45 degrees with horizontal with K.E of E. Its K.E. at highest point is
Correct answer: B. E/2
- A. Zero
- B. E/2
- C. E
- D. E/(2)1/2
Explanation
At 45°, the initial horizontal speed is v cos45° and the vertical speed is v sin45°. At the highest point the vertical speed is zero, so the remaining kinetic energy is E cos²45° = E × 1/2 = E/2. Students may choose zero by incorrectly assuming that the whole velocity becomes zero at the highest point, although only its vertical component is zero.
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About Projectile Motion
Projectile motion combines uniform horizontal motion with vertically accelerated motion under gravity, assuming air resistance is neglected. Questions use the components of initial velocity to find time of flight, maximum height, horizontal range and position, while distinguishing projectile motion from general circular or one dimensional motion.
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