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A stone is thrown upward from the top of a 59.4m high cliff with an upward velocity component of 19.6m/s how long is the stone in the air?

Correct answer: C. 6.00 s

  • A. 4.00 s
  • B. 5.00 s
  • C. 6.00 s
  • D. 7.00 s

Explanation

Taking upward as positive, the stone's height is h = 59.4 m + 19.6 m/s × t - 4.9 m/s^2 × t^2. Setting h = 0 gives t^2 - 4t - 12.12 = 0, so the positive root is about 6.0 s; the likely mistake is using only the upward-flight time, 19.6 m/s ÷ 9.8 m/s^2 = 2.0 s, and ignoring the fall from the cliff.

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About Projectile Motion

Projectile motion combines uniform horizontal motion with vertically accelerated motion under gravity, assuming air resistance is neglected. Questions use the components of initial velocity to find time of flight, maximum height, horizontal range and position, while distinguishing projectile motion from general circular or one dimensional motion.

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