Hl is a stronger base. It reduces H2SO4 to:
Correct answer: D. H2S
- A. S
- B. SO2
- C. H2SO3
- D. H2S
Explanation
H2S is correct because it is the product formed when Hl reduces H2SO4 due to the reduction of sulfur in sulfuric acid.
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About Oxidation and Reduction
Oxidation involves loss of electrons, increase in oxidation number or addition of oxygen, while reduction involves electron gain, decrease in oxidation number or removal of oxygen. The topic covers oxidising and reducing agents, oxidation-number changes, redox equations and the distinction between oxidation at the anode and reduction at the cathode.
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