Given below is part of a circuit diagram.If the resisters R1 = 5 ohms, R2 = 2 ohms, R3 = 4 ohms, R4 = 12 ohms, R5 = 5 ohms and the current passing through the circuit is 10 amperes. What is the potential difference across b and c?
Correct answer: B. 62V
- A. 112V
- B. 62V
- C. 58V
- D. 280V
Explanation
Given:Step 1: Simplify the parallel part (R₂, R₃, R₄)These 3 resistors are in parallel between b and the left of R₅:Use formula for parallel combination:1/R_parallel = 1/R₂ + 1/R₃ + 1/R₄= 1/2 + 1/4 + 1/12Let's calculate:So,R_parallel = 6/5 = 1.2 ΩStep 2: Add R₅ in seriesR₅ = 5 ΩSo total resistance from b to c:R_bc = R_parallel + R₅ = 1.2 + 5 = 6.2 ΩStep 3: Use Ohm's Law to find potential differenceV = I × R = 10 A × 6.2 Ω = 62 volts
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