Four times the greatest of three consecutive odd integers exceeds three times the least by 31. What is the greatest of the three consecutive odd integers?
Correct answer: C. 19
- A. 33
- B. 47
- C. 19
- D. 61
Explanation
To solve the problem, express the three consecutive odd integers as x, x + 2, and x + 4. The problem states that four times the greatest integer (x + 4) exceeds three times the least integer (x) by 31, giving the equation: 4(x + 4) = 3x + 31.Solving for x results in x = 15. Therefore, the greatest of the three integers is x + 4 = 19. Options 33, 47, and 61 do not satisfy the equation and lead to non-integer solutions for x, making them incorrect choices.
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