Formation of a tri-saccharide involves release of _ water molecule.

Explanation

1: This option suggests that the formation of a tri-saccharide involves the release of only one water molecule. However, the correct answer requires considering the number of water molecules released during the formation of each glycosidic bond in a tri-saccharide. 3: This option suggests that the formation of a tri-saccharide involves the release of three water molecules. However, this is not accurate. The number of water molecules released during the formation of a glycosidic bond depends on the type of glycosidic linkage being formed. 2: The correct option is 2. The formation of a tri-saccharide involves the linking of three sugar units (monosaccharides) through two glycosidic bonds. When a glycosidic bond is formed, a molecule of water (H2O) is released as a byproduct. This is a condensation reaction, where the hydroxyl group (-OH) from one sugar and a hydrogen atom from another sugar combine to form water (H2O), while the remaining oxygen and carbon atoms form the glycosidic bond between the two sugars. Since two glycosidic bonds are formed in a tri-saccharide, two water molecules are released during the process. 4: This option suggests that the formation of a tri-saccharide involves the release of four water molecules. However, this is not accurate, as explained above. The formation of two glycosidic bonds in a tri-saccharide results in the release of two water molecules. In summary, option c) 2 is the correct option. The formation of a tri-saccharide involves the release of two water molecules during the creation of two glycosidic bonds between three sugar units.