Force on a current carrying conductor in a uniform magnetic field is:
Correct answer: C. F = ILB sin α
- A. F = NIA cos α
- B. F = μnI
- C. F = ILB sin α
- D. F = ILA cos α
Explanation
The correct formula for the force exerted on a current-carrying conductor in a uniform magnetic field is F = ILB sin α. This formula indicates that the force (F) is proportional to the current (I), the length of the conductor (L), and the magnetic field strength (B), and it depends on the sine of the angle (α) between the conductor and the magnetic field direction. Increased values of these variables result in a stronger force.Option A is incorrect as it represents a torque-related formula, Option B is unrelated to this context as it involves magnetic permeability, and Option D incorrectly uses cos α, which is irrelevant for calculating magnetic force in this context.
This question appeared on the UHS MDCAT 2010 paper, which you can sit online with every answer explained.
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About Magnetic Flux Density
Magnetic flux density measures the magnetic force acting on a current carrying conductor or moving charge in a magnetic field. Work includes the relations B equals F divided by IL and F equals qvB, the tesla as its SI unit, field direction and the distinction between flux density and magnetic flux.
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