'F' is the maximum force acting on a conductor. Now if we change the direction of the conductor by making an angle of 45° with the magnetic field, then the force becomes:
Correct answer: C. F/√2
- A. F/2
- B. 2F
- C. F/√2
- D. √2 F
Explanation
As we know, the force experienced by the current-carrying conductor is given by F'=IBLsinθ If θ= 45o F'=Fsin45° F'=F(0.707) F'=F/√2
Last updated
About Magnetic Flux Density
Magnetic flux density measures the magnetic force acting on a current carrying conductor or moving charge in a magnetic field. Work includes the relations B equals F divided by IL and F equals qvB, the tesla as its SI unit, field direction and the distinction between flux density and magnetic flux.
Practise Electromagnetism
1,176 free Electromagnetism MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1 Gauss is equivalent to:
1 Weber / m² is equal to __________?
A 100m long conductor carrying current of 2A is at right angle to B of 0.5 wb_m² . The force experienced by the conductor is:
A 2m wire carrying current 5A is at right angle to uniform magnetic field of 0.2 Web/m². The force on wire will be:
A current carrying coil is placed in a uniform magnetic field.The torque produced in this coil will be doubled when the