'F' is the maximum force acting on a conductor. Now if we change the direction of the conductor by making an angle of 45° with the magnetic field, then the force becomes:
Correct answer: C. F/√2
- A. F/2
- B. 2F
- C. F/√2
- D. √2 F
Explanation
As we know, the force experienced by the current-carrying conductor is given by F'=IBLsinθ If θ= 45o F'=Fsin45° F'=F(0.707) F'=F/√2
This question appeared on the UHS MDCAT 2016 paper, which you can sit online with every answer explained.
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About Magnetic Flux Density
Magnetic flux density measures the magnetic force acting on a current carrying conductor or moving charge in a magnetic field. Work includes the relations B equals F divided by IL and F equals qvB, the tesla as its SI unit, field direction and the distinction between flux density and magnetic flux.
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