For water at 300°C, it has a vapour pressure 8592.7 kPa and fugacity 6738.9 kPa Under these conditions, one mole of water in liquid phase has a volume of 25.28 cm3 and that in vapour phase in 391.1 cm3.Fugacity of water (in kPa) at 9000 kPa will be__________________?
Correct answer: B. 6753.5
- A. 6738.9
- B. 6753.5
- C. 7058.3
- D. 9000
Explanation
For the compressed liquid, fugacity changes approximately as f = fsat exp[Vl(P − Psat)/(RT)]. Substitution of the given liquid molar volume and pressure increase gives about 6753.5 kPa, rather than the saturation value 6738.9 kPa.
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