For the chemical equilibrium A+2B⇌2C, the value of the equilibrium constant, K, is 10. What is the value for the equilibrium constant for the reaction written in reverse? 2C⇌A+2B
Correct answer: A. 0.10
- A. 0.10
- B. 0.20
- C. 40
- D. 400
- E. 100
Explanation
The equilibrium constant is defined as the ratio of product concentrations to reactant concentrations. When you reverse a reaction, the original products become the new reactants and the original reactants become the new products. Mathematically, this flips the fraction, meaning the new constant is 1 divided by the old constant (1/10 = 0.1)Options B, C, D, and E are incorrect as they do not accurately calculate the equilibrium constant for the reverse reaction and provide values that deviate from the correct answer of 0.10. It's important to understand how to manipulate equilibrium constants when considering reactions in reverse.
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About Chemical Equilibrium
Reversible reactions reach dynamic equilibrium when forward and reverse rates become equal, and Le Chatelier's principle predicts the effect of changing concentration, pressure or temperature. The chapter also covers solubility product, the common ion effect, buffer action and the conditions used in Haber's process, with equilibrium shifts distinguished from changes in the equilibrium constant.
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