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For a transistor, the current amplification factor α = 0.9. This transistor is connected in a common emitter configuration. When the base current changes by 0.4 mA, the change in collector current will be:

Correct answer: D. 3.6 mA

  • A. 36 mA
  • B. 9 mA
  • C. 4 mA
  • D. 3.6 mA

Explanation

β = α/(1-α) = 0.9/0.1 = 9. Change in collector current ΔIC = β × ΔIB = 9 × 0.4 = 3.6 mA.

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A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.

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