For a gas where volume and pressures are 1dm3 and 2 atm respectively what should be its new volume when pressure is increased to 6 atm at constant temperature ?
Correct answer: B. 1/3dm3
- A. 1/2dm3
- B. 1/3dm3
- C. 1/4dm3
- D. 2/3dm3Trying Interactive Physics Simulation Software
Explanation
At constant temperature, Boyle's law gives P1V1 = P2V2. Thus V2 = (2 atm)(1 dm3)/(6 atm) = 1/3 dm3. The likely mistake is 1/2 dm3, which uses the original pressure rather than the new pressure in the calculation.
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About Boyle's Law
Boyle's law states that the pressure of a fixed mass of gas varies inversely with its volume when temperature remains constant. Problems use the relationship P₁V₁ = P₂V₂, pressure-volume graphs and volume changes, with constant temperature distinguishing it from Charles's law.
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