Find the amplitude of an object oscillating at the end of a spring, if the equation for its position at any instant t is given by x=0.258cos(1/8 t).
Correct answer: A. 0.258 m
- A. 0.258 m
- B. π/9 m
- C. 25m
- D. None of these
Explanation
In the given equation x=0.258cos(1/8 t), the coefficient of cos(1/8 t) is the amplitude of the oscillation. Therefore, the amplitude of the object oscillating at the end of the spring is 0.2580.258 m.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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