The period of oscillation of a mass m suspended from a spring is T. Then the period of a mass 4m will be:
Correct answer: B. 1/2 s
- A. 1/4 S
- B. 1/2 s
- C. 2 s
- D. 4 s
Explanation
The period of oscillation of a mass-spring system is given by T=2π(m/K)^1/2 , where m is the mass and k is the spring constant. Since the period T is directly proportional to m/K , doubling the mass will increase the period by a factor of 2 . Therefore, the period for the mass 4m will be T/2 , or 1/2 s.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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