Ethyne on oxidation with strong alkaline KMnO4 forms:
Correct answer: B. Oxalic acid
- A. Hydrochloric acid
- B. Oxalic acid
- C. Acetic acid
- D. Formic acid
Explanation
When ethyne is oxidized with strong alkaline potassium permanganate (KMnO4), it forms oxalic acid. The reaction is as follows: C2H2 + 4KMnO4 + 6H2O → 2(COOH)2 + 4KOH + 4MnO2. In this reaction, the ethyne molecule is oxidized to oxalic acid. The potassium permanganate (KMnO4) is reduced to manganese dioxide (MnO2). The water (H2O) is a reactant and a product.Option A, C, and D are incorrect as they do not represent the correct product formed when ethyne is oxidized with strong alkaline KMnO4, which is oxalic acid.
Last updated
About Chemistry of Hydrocarbons
Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
Practise Chemistry of Hydrocarbons
1,091 free Chemistry of Hydrocarbons MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1-Butene and two Butene are showing which type of isomerism?
1-butyne and 2-butyne can be identified by using which of the following reagents
2-chloropropane is heated with Na metal product is 2,3-dimethyl butane, reaction is:
2-methyl propene is isomeric with but-1-ene. They can be distinguished by:
2-methyl propene is isomeric with butene-1. They can be distinguished by: