Ethyne on oxidation with strong alkaline KMnO4 forms:
Correct answer: B. Oxalic acid
- A. Hydrochloric acid
- B. Oxalic acid
- C. Acetic acid
- D. Formic acid
Explanation
When ethyne is oxidized with strong alkaline potassium permanganate (KMnO4), it forms oxalic acid. The reaction is as follows: C2H2 + 4KMnO4 + 6H2O → 2(COOH)2 + 4KOH + 4MnO2. In this reaction, the ethyne molecule is oxidized to oxalic acid. The potassium permanganate (KMnO4) is reduced to manganese dioxide (MnO2). The water (H2O) is a reactant and a product.Option A, C, and D are incorrect as they do not represent the correct product formed when ethyne is oxidized with strong alkaline KMnO4, which is oxalic acid.
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Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
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