Ethylene bromide on treatment with Zn gives:
Correct answer: B. Alkene
- A. Alkyne
- B. Alkene
- C. Alkane
- D. All of these
Explanation
When ethylene bromide is treated with zinc (Zn), it undergoes dehydrohalogenation, resulting in the formation of an alkene, specifically ethene. Alkenes are characterized by a carbon-carbon double bond. The other options are incorrect because:Alkynes require the removal of more hydrogen atoms to form carbon-carbon triple bonds, which is not the case here.Alkanes would require hydrogen addition, not removal, to form single bonds.'All of these' is incorrect because only one type of hydrocarbon (alkene) is formed.
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Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
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