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Equal volumes of 1 M each of KMnO4 and K2Cr2O7 are used to oxidise Fe(II) solution in acidic medium. The amount of Fe oxidized will be :

Correct answer: C. More with K2Cr2O7

  • A. More with KMnO4
  • B. Equal with both oxidizing agents
  • C. More with K2Cr2O7
  • D. Cannot be determined

Explanation

Both KMnO4 and K2Cr2O7 are strong oxidizing agents that can oxidize Fe(II) to Fe(III) in acidic medium. The n-factor of KMnO4 in acidic medium is 5, while for K2Cr2O7, it is 6. This means that for the same number of moles, K2Cr2O7 can transfer more electrons and thus oxidize more moles of Fe(II). Therefore, K2Cr2O7 will oxidize more Fe(II) compared to KMnO4. Option A is incorrect because KMnO4 has a lower n-factor. Option B is incorrect because the n-factors are different, leading to different amounts of Fe(II) oxidized. Option D is incorrect because the comparison of n-factors provides a clear determination.

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