Equal volumes of 1 M each of KMnO₄ and K₂Cr₂O₇ are used to oxidize Fe(II) solution in an acidic medium. The amount of Fe oxidized will be:
Correct answer: C. More with K₂Cr₂O₇
- A. More with KMnO4
- B. Equal with both oxidizing agents
- C. More with K₂Cr₂O₇
- D. Cannot be determined
Explanation
The oxidizing capacity depends on the number of electrons transferred (the n-factor). For KMnO₄, the n-factor is 5 (Mn⁷⁺ → Mn²⁺). For K₂Cr₂O₇, the n-factor is 6 (2Cr⁶⁺ → 2Cr³⁺). Since equal moles are used, K₂Cr₂O₇ will accept more electrons and thus oxidize more Fe(II).
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