Electrolysis of dilute solution of NaCI results at the anode
Correct answer: C. Chlorine
- A. Sodium
- B. Hydrogen
- C. Chlorine
- D. Oxygen
Explanation
The correct option for the product at the anode during the electrolysis of a dilute solution of sodium chloride (NaCl) is:(c) chlorineHere's why:Anode: During electrolysis, the positive electrode (anode) attracts negatively charged ions. In this case, the chloride ions (Cl-) from NaCl migrate towards the anode.Chlorine formation: At the anode, chloride ions lose electrons and undergo oxidation, forming chlorine gas (Cl2):2Cl- (aq) -> Cl2(g) + 2e-Sodium and hydrogen: Sodium ions (Na+) are present in the solution but are less likely to discharge at the anode compared to chloride ions due to their lower oxidation potential. Additionally, water molecules at the anode can also undergo oxidation, albeit with a higher potential, leading to the formation of oxygen gas (O2) and hydrogen ions (H+).Dilute solution: In a dilute solution of NaCl, the concentration of water molecules is significantly higher than Cl- ions. This makes the reaction with water more prominent, leading to some oxygen and hydrogen evolution alongside chlorine production.Therefore, although minor side reactions might occur, the primary product formed at the anode during the electrolysis of dilute NaCl solution is chlorine gas (Cl2).
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The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.
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