Each carbon atom in alkane has hybridization
Correct answer: B. Sp³
- A. Sp
- B. Sp³
- C. Sp²
- D. dsp²
Explanation
In alkanes, each carbon atom forms sigma bonds with four other atoms, either carbon or hydrogen. This requires the carbon atom to have four available orbitals to form these bonds. The sp³ hybridization allows one s orbital and three p orbitals to combine, forming four sp³ hybrid orbitals, which can each participate in a sigma bond.
Last updated
About Chemistry of Hydrocarbons
Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
Practise Chemistry of Hydrocarbons
1,091 free Chemistry of Hydrocarbons MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1-Butene and two Butene are showing which type of isomerism?
1-butyne and 2-butyne can be identified by using which of the following reagents
2-chloropropane is heated with Na metal product is 2,3-dimethyl butane, reaction is:
2-methyl propene is isomeric with but-1-ene. They can be distinguished by:
2-methyl propene is isomeric with butene-1. They can be distinguished by: