During each cycle, a heat engine with an efficiency of 25% takes in 800 J of energy. How much waste heat is expelled during each cycle?

Correct answer: E. 600 J

  • A. 100 J
  • B. 200 J
  • C. 300 J
  • D. 400 J
  • E. 600 J

Explanation

Efficiency =( useful power out ÷ total power in) x 100 If the efficiency of the engine is 25%, then the energy that is output for useful work is 25% of the input energy, which is (25%)(800 J) = 200 J. The remaining 800 J - 200 J = 600 J is expelled as waste heat.

This question appeared on the NUMS 2017 paper, which you can sit online with every answer explained.

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About First Law of Thermodynamics

The first law relates heat supplied, work done and the change in internal energy through energy conservation. Problems use sign conventions and apply the law to isothermal, adiabatic, isobaric and isochoric processes. Internal energy is a state function, while heat and work depend on the path followed.

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