During adiabatic compression work done is equal to 200 J. What will be the change in internal energy?
Correct answer: B. +200 J
- A. -200 J
- B. +200 J
- C. 100 J
- D. 0 J
Explanation
In an adiabatic system no heat exchange between the system and surrounding. In adiabatic compression work done by the system is negative so the change in internal energy will be positive. Or -W=U Since work done by the system is -200 J The change in internal energy will be +200 J
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About First Law of Thermodynamics
The first law relates heat supplied, work done and the change in internal energy through energy conservation. Problems use sign conventions and apply the law to isothermal, adiabatic, isobaric and isochoric processes. Internal energy is a state function, while heat and work depend on the path followed.
Practise Thermodynamics
714 free Thermodynamics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More First Law of Thermodynamics questions
For a heat engine 'A' the ratio of Q2 to Q1 is 2/3 while for that of heat engine 'B', the ratio of Q2 to Q1 is 1/3. What is the value ηA: ηB?
What is the factor upon which change in internal energy of an ideal gas depends?
A heat engine working according to the second law of thermodynamics has 50% efficiency.What will be the temperature of its low-temperature reservoir if the high-temperaturereservoir is 327 K?
If heat energy of 100 J is taken out but 400 J work is done on the system, the change in internal energy is:
Heat and work are equivalent. This means
A system can be taken from the initial state P1V1 to the final state P2V2 by two different methods. Let Q and W represent the heat given to the system and the work done by the system.Which of the following must be the same in both the methods?