A heat engine working according to the second law of thermodynamics has 50% efficiency.What will be the temperature of its low-temperature reservoir if the high-temperaturereservoir is 327 K?
Correct answer: A. 27 0C
- A. 27 0C
- B. 127 0C
- C. 300 0 C
- D. 600 0 C
Explanation
327k means 327-273-54 degrees celsius. For a reservoir to work at a 50% efficiency, the low reservoir must have half the temperature than the high reservoir, which makes the temperature 27 degrees celsius. As it is a numerical, it can have only one possible answer.
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About First Law of Thermodynamics
The first law relates heat supplied, work done and the change in internal energy through energy conservation. Problems use sign conventions and apply the law to isothermal, adiabatic, isobaric and isochoric processes. Internal energy is a state function, while heat and work depend on the path followed.
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