Decreasing order of size of various hybrid orbitals is:
Correct answer: B. sp3>sp2>sp
- A. sp>sp2>sp3
- B. sp3>sp2>sp
- C. sp2>sp>sp3
- D. sp>sp3>sp2
Explanation
The order "sp³ > sp² > sp" represents the decreasing degree of p-character in hybrid orbitals. In sp³ hybridization, there is a higher proportion of p-character, leading to a tetrahedral geometry with 109.5° bond angles. In sp² hybridization, the p-character decreases, resulting in a trigonal planar geometry with 120° bond angles. In sp hybridization, the p-character is the lowest, creating a linear geometry with 180° bond angles.
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