Consider the given monohybrid cross between pure breeding pea plants with green and yellow seeds.If total 76 pea plants are produced in the F2 generation, then the number of pea plants with yellow seeds would be:
Correct answer: C. 57
- A. 19
- B. 38
- C. 57
- D. 75
Explanation
In a monohybrid cross of pea plants, where yellow seeds are dominant over green, if 76 plants are produced in the F2 generation, approximately 57 would be expected to have yellow seeds. This is based on the 3:1 phenotypic ratio of dominant to recessive traits observed in the F2 generation of a monohybrid cross. 3/4 of the F2 generation is expected to have yellow seeds, you would calculate 76 * (3/4) = 57. So option C is correct. All other options give wrong number of plants with yellow seeds.
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About Mendel's Laws of Inheritance
Mendelian inheritance explains how alleles separate into gametes and assort during reproduction, producing predictable genotype and phenotype ratios. Questions cover dominance, recessiveness, homozygous and heterozygous conditions, the laws of segregation and independent assortment, monohybrid and dihybrid crosses, test crosses and the limits caused by linked genes.
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