Consider the given cross between pure breeding yellow round and green wrinkled seeds of pea plants.If total 568 pea plants are produced in the F2 generation, then the possible number of pea plants with green round seeds (yyRr) would be:
Correct answer: C. 106
- A. 35
- B. 71
- C. 106
- D. 279
Explanation
In a dihybrid cross between pea plants with pure-breeding yellow round and green wrinkled seeds, the F2 generation will exhibit a phenotypic ratio of 9:3:3:1. With a total of 568 plants, the number of green round plants is (3/16) * 568 = 106.5. Since you can't have half a plant, you'd round to the nearest whole number, resulting in 106 green round plants. Option C is correct as it is closest to the answer.
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About Mendel's Laws of Inheritance
Mendelian inheritance explains how alleles separate into gametes and assort during reproduction, producing predictable genotype and phenotype ratios. Questions cover dominance, recessiveness, homozygous and heterozygous conditions, the laws of segregation and independent assortment, monohybrid and dihybrid crosses, test crosses and the limits caused by linked genes.
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