Chlorination of methane is believed to proceed through free radical mechanism. Which of the following is propagation step?
Correct answer: B. CH3 + Cl2 -----> CI + CH3-CI
- A. CI-CI ---->2Cl
- B. CH3 + Cl2 -----> CI + CH3-CI
- C. CH3+ HCl ----->H'+ H3C-Cl
- D. All of these
Explanation
Option B is correct.The propagation step in the chlorination of methane is the step where a free radical reacts with a reactant molecule to form a new product and another free radical. The propagation step for the chlorination of methane is: Cl + CH4 → CH3Cl + Cl In this step, a chlorine radical reacts with a methane molecule to form chloromethane and another chlorine radical. The chlorine radical is then free to react with another methane molecule, and the reaction continues in a chain reaction.Options A, C, and D are incorrect as they do not represent the propagation step accurately. Option A describes the initiation step, Option C involves a different reaction, and Option D is a misleading choice as not all options are correct.
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Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
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