Calculate the work done in a resistor of 20 ohm carrying 5A of current in 3 hours.

Correct answer: B. 1.5 KWh

  • A. 1 KWh
  • B. 1.5 KWh
  • C. 2 KWh
  • D. 3 KWh

Explanation

1kWh is the power output multiplied by the number of hours the appliance is used. Power is found by voltage x current, and the voltage is found by Resistance x Current. So (20x5)(5)(3) gives 1.5kWh. We can use the formula: P = V x I To use this formula, we need to find the voltage, which can be calculated using the formula: voltage = resistance x current So, voltage = 20 ohm x 5A = 100 V Next, we can calculate the energy in watt-hours using the formula: energy (in watt-hours) = power (in watts) x time (in hours) Substituting the values we have: energy (in watt-hours) = (100 V x 5 A) x 3 hours = 1500 watt-hours Finally, we can convert watt-hours to kilowatt-hours (kWh) by dividing by 1000: energy (in kWh) = 1500 watt-hours / 1000 = 1.5 kWh Therefore, the power consumed is 1.5 kWh.

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Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.

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