An object is thrown with velocity v from the edge of a cliff above level ground. Neglect air resistance. In order for the object to travel a maximum horizontal distance from the cliff before hitting the ground, the throw should be at an angle 0 with respect to the horizontal of
Correct answer: C. greater than zero but less than 45° above the horizontal
- A. greater than 60° above the horizontal
- B. greater than 45° but less than 60° above the horizontal
- C. greater than zero but less than 45° above the horizontal
- D. greater than zero but less than 45° below the horizontal
Explanation
In projectile motion, the optimal angle for maximum horizontal distance when launching from an elevation is less than 45°. While 45° is optimal for maximum range on a flat plane, launching from a height means a smaller angle provides a longer time in the air and a larger horizontal velocity component, increasing the total horizontal distance. Angles greater than 45° increase the vertical component, reducing range, and angles below the horizontal severely limit both time in the air and horizontal distance. Therefore, an angle greater than zero but less than 45° above the horizontal is ideal.
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