A 10 kg wagon rests on an inclined plane. The plane makes an angle of 30° with the horizontal. Approximately how large is the force required to keep the wagon from sliding down the plane( Note: sin30°=0.5;cos30°=0.866)
Correct answer: B. 49N
- A. 10N
- B. 49N
- C. 85N
- D. 98N
Explanation
The correct answer is Option B: 49N. To find the force required to keep the wagon from sliding down, we calculate the component of the gravitational force acting parallel to the inclined plane. This force is given by the formula: F_parallel = m * g * sin(θ), where m is the mass of the wagon (10 kg), g is the acceleration due to gravity (approximately 9.8 m/s²), and θ is the angle of the incline (30°). Substituting these values, we have F_parallel = 10 kg * 9.8 m/s² * 0.5 = 49N. This is the force required to prevent the wagon from sliding down. The other options either underestimate or overestimate the force needed.
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