An element of the third period (Na to S) is boiled in chlorine. The product is purified and then added to water. The resulting solution Is found to be neutral. What is the element?
Correct answer: A. Sodium
- A. Sodium
- B. Aluminium
- C. Silicon
- D. Phosphorus
Explanation
The correct answer is A. Sodium.When an element from the third period (Na to S) is boiled in chlorine, it forms a compound called sodium chloride (NaCl). This compound, when dissolved in water, dissociates into sodium ions (Na⁺) and chloride ions (Cl⁻). The balance of these ions results in a neutral solution due to the cancellation of positive and negative charges. Sodium fits these properties, making it the correct answer. The other options (Aluminum, Silicon, and Phosphorus) do not exhibit the same chemical behaviors as sodium and would not lead to a neutral solution in this scenario.
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About s-Block and p-Block Elements
The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.
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