Amongst the following elements (whose electronic configuration are given below),the one having the highest ionization energy is:

Correct answer: B. [Ne] 3s2 3p3

  • A. [Ne] 3s2 3p1
  • B. [Ne] 3s2 3p3
  • C. [Ne] 3s2 3p2
  • D. [Ar] 3d10 4s2 4p1

Explanation

Ionization energy increases as a shell fills. Half filled or completely filled orbitals are very stable and so it is difficult to ionize such elements having half-filled or completely filled shells. In 3d subshell maximum 10 electrons can be accomodated. In [Ne] 3s2 3p3 , the valance shell is half filled so it has higher ioniztion energy. Therefore, option B is the correct answer.

Written and checked by , M.Phil ChemistryLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

About Periodic Properties and Trends

Periodic properties arise from electron configuration and effective nuclear charge, producing trends in atomic and ionic radius, ionization energy, electron affinity, electronegativity, metallic character and reactivity. Comparisons run across periods and down groups, with attention to common exceptions. The topic also relates these trends to the behavior of s-block and p-block elements.

Practise s-Block and p-Block Elements

1,359 free s-Block and p-Block Elements MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Chemistry questions like this

Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Periodic Properties and Trends questions