Albinism is a recessive trait. A normal woman with albino father and normal mother marries an albino man. What is the probability of albinism in her children?
Correct answer: D. 100%
- A. Zero %
- B. 25%
- C. 50%
- D. 100%
Explanation
To determine the probability of albinism in the children of this couple, we can use Punnett squares.Let's denote the normal allele as "N" and the albino allele as "n."The normal woman is homozygous for the normal allele (NN), while her father is homozygous for the albino allele (nn). The albino man is also homozygous for the albino allele (nn).Normal woman's genotype: NNAlbino father's genotype: nnAlbino man's genotype: nnWhen crossed:Normal woman (NN) x Albino man (nn)The Punnett square: N N n NN NN n Nn NnSo, all offspring (100%) will be heterozygous carriers of the albino allele (Nn). This means that while none of the children will display the albino phenotype, they will all carry one copy of the albino allele and have a 0% probability of being albino themselves.
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Mendelian inheritance explains how alleles separate into gametes and assort during reproduction, producing predictable genotype and phenotype ratios. Questions cover dominance, recessiveness, homozygous and heterozygous conditions, the laws of segregation and independent assortment, monohybrid and dihybrid crosses, test crosses and the limits caused by linked genes.
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