Acidified potassium permanganate acts as a strong oxidising agent and in doing so the purple manganate seven ion is reduced to

Correct answer: A. the almost colourless manganese two ion

  • A. the almost colourless manganese two ion
  • B. manganese metal
  • C. the green manganate six ion
  • D. brown manganese dioxide

Explanation

In acidic solution permanganate is reduced from plus 7 to plus 2, and the sharp change from deep purple to almost colourless is what makes it self indicating in titrations. In neutral or alkaline conditions the reduction stops at manganese dioxide, giving a brown precipitate instead. The acid used must be dilute sulphuric acid, since hydrochloric acid would itself be oxidised to chlorine.

Written and checked by , M.Phil ChemistryLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? support@testustad.com

About Electronic Structure of d-Block Elements

The electronic structure of d-block elements covers the filling of the (n-1)d and ns orbitals, general electronic configurations, and the exceptions shown by chromium and copper. It explains how partially filled d orbitals produce variable oxidation states, coloured ions, magnetic behaviour and complex formation, while distinguishing transition elements from elements with completely filled d subshells.

Practise Transition Elements

531 free Transition Elements MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Chemistry questions like this

Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Electronic Structure of d-Block Elements questions