According to the Hardy-Weinberg theorem, what will be the frequency of heterozygote when 'p' is 0.2?
Correct answer: A. 0.32
- A. 0.32
- B. 0.38
- C. 0.42
- D. 0.48
Explanation
According to the Hardy-Weinberg theorem, the frequency of heterozygotes (denoted as q) can be calculated using the formula: q = 2 * p * (1 - p), where p represents the frequency of one allele in a population. Given that p is 0.2 (or 20% in decimal form), we can substitute this value into the equation: q = 2 * 0.2 * (1 - 0.2) = 2 * 0.2 * 0.8 = 0.32. Therefore, the frequency of heterozygotes (q) would be 0.32 or 32%.
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Evolution describes heritable change in populations over generations through variation, natural selection and adaptation. Lamarckism explains inheritance of acquired characteristics, while Darwinism explains selection of favourable inherited variations; these historical explanations must not be confused with the modern genetic account of evolutionary change.
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