A wire of uniform area of cross-section 'A' and length 'L' is cut into two equal parts. The resistivity of each part is?
Correct answer: C. Remains the same
- A. Doubled
- B. Half
- C. Remains the same
- D. Increase three times
Explanation
Resistivity is the property of the material in the wire that depends on the chemical composition of the material but not on the amount of material or the shape (length, cross-sectional area) of the material. Hence, resistivity "remains the same" while the resistance changes based on the length and cross-section of the wire.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Current Electricity
Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.
Practise Current Electricity
1,052 free Current Electricity MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Current Electricity questions
A resistance of 40 Ohms is attached to a circuit having current of 300 Amperes. Find the voltage:
A current of 16 amperes divides between two branches in parallel of resistances 8 ohms and 12 ohms respectively. The current in each branch is:
Which of the following statements is true?
Resistance of a material always decreases if:
EMF becomes equal to terminal potential difference when
In order to achieve accuracy, the slide wire of a potentiometer should be: