A current of 16 amperes divides between two branches in parallel of resistances 8 ohms and 12 ohms respectively. The current in each branch is:
Correct answer: B. 6.4 A, 9.6 A
- A. 6.4 A, 6.9 A
- B. 6.4 A, 9.6 A
- C. 4.6 A, 6.9 A
- D. 4.6 A, 9.6 A
Explanation
The current flows through a resistor R1=I1= I ( R2 ) / R1 + R2 = 16×(12/20) = 9.6 AThe current flows through the resistor R2=I2= I ( R1 ) / R1 + R2 = 16×(8/20) = 6.4 A
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